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50=-16x^2+99.2x
We move all terms to the left:
50-(-16x^2+99.2x)=0
We get rid of parentheses
16x^2-99.2x+50=0
a = 16; b = -99.2; c = +50;
Δ = b2-4ac
Δ = -99.22-4·16·50
Δ = 6640.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99.2)-\sqrt{6640.64}}{2*16}=\frac{99.2-\sqrt{6640.64}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99.2)+\sqrt{6640.64}}{2*16}=\frac{99.2+\sqrt{6640.64}}{32} $
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